# Calculation Of Materials For Plastering

Posted in Student Corner | Email This Post |Here, we will be calculating the quantities of materials i.e., cement and sand, required for plastering. We will take 100 sq. metre area of wall and calculate accordingly. Moreover, some extra percentages are taken on volume for other construction works during the process.

**Assuming thickness of plastering,**

Inside = 12 mm

Outside = 20 mm

Ceiling = 6 mm

__FOR 12 mm PLASTERING__

Let us consider 100 sq. metre of wall.

Volume of plastering = 100 x 0.012 = 1.2 m^{3}

Adding 30% to fill up the joints = 1.2 + 1.2 x (30/100) = 1.56 m^{3}

Increasing 20% for dry volume = 1.56 + 1.56 x (20/100) = 1.87 m^{3}

approx 2 m^{3}

**For 1:6 cement mortar,**

Volume of cement = 2 / (1+6) = 0.29 m^{3}

Volume of sand = 2 – 0.29 = 1.71 m^{3}

No of bags for cement = 0.29 / 0.0347 (Volume of 1 bag of cement = 0.0347 m^{3}) = 8.36

**Approx 8.5 bags**

**For 1:5 cement mortar,**

Volume of cement = 2 / (1+5) = 0.33 m^{3}

Volume of sand = 2 – 0.33 = 1.67 m^{3}

No of bags for cement = 0.33 / 0.0347 = 9.51

**Approx 10 bags**

Similarly,

__FOR 20 mm PLASTERING__

Volume of plastering = 100 x 0.02 = 2 m^{3}

Adding 20% to fill up the joints = 2 + 2 x (20/100) = 2.4 m^{3}

Increasing 20% for dry volume = 2.4+ 2.4 x (20/100)

(30% can also be used) = 2.88 m^{3}

approx 3 m^{3}

**For 1:6 cement mortar,**

Volume of cement = 3 / (1+6) = 0.43 m^{3}

Volume of sand = 3 – 0.43 = 2.57 m^{3}

No of bags for cement = 0.43 / 0.0347 = 12.4

**Approx 12.5 bags**

**For 1:5 cement mortar,**

Volume of cement = 3 / (1+5) = 0.5 m^{3}

Volume of sand = 3 – 0.5 = 2.5 m^{3}

No of bags for cement = 0.5 / 0.0347 = 14.4

**Approx 14.5 bags**

__FOR 6 mm PLASTERING__

Volume of plastering = 100 x 0.006 = 0.6 m^{3}

Adding 20% to fill up the joints = 0.6 + 0.6 x (20/100) = 0.72 m^{3}

Increasing 20% for dry volume = 0.72 + 0.72 x (20/100) = 0.86 m^{3}

Approx 1 m^{3}

**For 1:5 cement mortar,**

Volume of cement = 1 / (1+5) = 0.17 m^{3}

Volume of sand = 1 – 0.17 = 0.83 m^{3}

No of bags for cement = 0.17 / 0.0347 = 4.89

**Approx 5 bags**

**For 1:4 cement mortar,**

Volume of cement = 1 / (1+4) = 0.2 m^{3}

Volume of sand = 1 – 0.2 = 0.8 m^{3}

No of bags for cement = 0.2 / 0.0347 = 5.76

**Approx 6 bags**