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# Mortar Calculation in Brickwork

Size of brick with Mortar = 20 cm × 10 cm × 10 cm

No. of bricks required per 1 m3 brickwork = 1 / (0.2 × 0.1 × 0.1) = 500 nos.

No. of bricks for 10 m3 brickwork = 500 × 10 = 5000 nos.
Size of brick without Mortar = 19 cm × 9 cm × 9 cm
Actual volume of 5000 bricks = 5000 × (0.19 × 0.09 × 0.09) = 5000 × 0.001539 = 7.695 m3
approx 7.7 m3

Volume of mortar = 10 – 7.7 = 2.3 m3
Adding 10% wastage = 2.3 + 2.3 × 10% = 2.53 m3
Adding 25% for dry mortar weight (Dry mortar weight > wet mortar weight)
Volume of dry mortar = 2.53 + 2.53 × 25% = 3.16 m3
approx 3.2 m3

Now,
For 1: 6 cement mortar,
Volume of cement = 3.2 / 7 = 0.45 m3
Volume of sand = 3.2 – 0.45 = 2.7 m3
1 m3 OPC (Ordinary Portland Cement) = 1440 kg
Weight of 1 bag of cement = 50 kg
Volume of 1 bag of cement = 50 / 1440 = 0.0347 m3
For 10 m3 of brickwork, no. of cement bags needed = 0.45 / 0.0347 = 12.97
approx 13 bags

Similarly,
For 1: 5 cement mortar,
Volume of cement = 3.2 / 6 = 0.53 m3
Volume of sand = 3.2 – 0.53 = 2.67 m3
1 m3 OPC (Ordinary Portland Cement) = 1440 kg
Weight of 1 bag of cement = 50 kg
Volume of 1 bag of cement = 50 / 1440 = 0.0347 m3
For 10 m3 of brickwork, no. of cement bags needed = 0.53 / 0.0347 = 15.27
approx 15 bags

For 1: 4 cement mortar,
Volume of cement = 3.2 / 5 = 0.64 m3
Volume of sand = 3.2 – 0.64 = 2.56 m3
1 m3 OPC (Ordinary Portland Cement) = 1440 kg
Weight of 1 bag of cement = 50 kg
Volume of 1 bag of cement = 50 / 1440 = 0.0347 m3
For 10 m3 of brickwork, no. of cement bags needed = 0.64 / 0.0347 = 18.44
approx 18 bags

For 1: 3 cement mortar,
Volume of cement = 3.2 / 4 = 0.8 m3
Volume of sand = 3.2 – 0.8 = 2.4 m3
1 m3 OPC (Ordinary Portland Cement) = 1440 kg
Weight of 1 bag of cement = 50 kg
Volume of 1 bag of cement = 50 / 1440 = 0.0347 m3
For 10 m3 of brickwork, no. of cement bags needed = 0.8 / 0.0347 = 23.05
approx 22.5 bags

For 1: 2 cement mortar,
Volume of cement = 3.2 / 3 = 1.07 m3
Volume of sand = 3.2 – 1.07= 2.13 m3
1 m3 OPC (Ordinary Portland Cement) = 1440 kg
Weight of 1 bag of cement = 50 kg
Volume of 1 bag of cement = 50 / 1440 = 0.0347 m3
For 10 m3 of brickwork, no. of cement bags needed = 1.07 / 0.0347 = 30.83
approx 30 bags

 Ratio Cement Sand 1:2 1 m3 (30 bags) 2 m3 1:3 0.75 m3 (22.5 bags) 2.25 m3 1:4 0.6 m3 (18 bags) 2.4 m3 1:5 0.5 m3 (15 bags) 2.5 m3 1:6 0.45 m3 (13 bags) 2.7 m3

As per standard values,

### Kanwarjot Singh

Kanwarjot Singh is the founder of Civil Engineering Portal, a leading civil engineering website which has been awarded as the best online publication by CIDC. He did his BE civil from Thapar University, Patiala and has been working on this website with his team of Civil Engineers.

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## 11 comments on "Mortar Calculation in Brickwork"

Jayasankar says:

Very good useful

Chuol pal says:

I need more knowledge about the basic information in civil engineer work at field work site because I am fresh graduate

Herbz says:

This formula assumes that all the faces of the brick are filled with mortar which isn’t true because the front and back faces of the brick are left for plastering

very simple way to explain everything needed…..thumbs up

Farooq bashir says:

Thanks, for the Very useful Information and Guide.
Actually, this is very important for the all Construction Workers.

Farooq Bashir says:

Very Technical, and Useful. Thank You.

Mohamed Munowfeer says:

easily we can understand thanks

OLAL Andrew says:

Thank you for guidance. Can you determine the motor requirements for all the sizes of the bricks. Will be very grateful.

Ravi Kethavath says:

Check the summary made for 10 cum of bricks,it’s not mentioned in summary,you have without quantity of bricks.

Kumar Praja Nepal says:

Nice too Meet you Too

Talemwa julius says:

Thanks