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Fluid Jets

Where the effect of air resistance is small, the path of projectile is followed when a fluid discharged through an orifice into the air
The initial velocity of the jet is

V0 = Cv?2gh

where h= head on center line of orifice, ft (m),
Cv =coefficient of velocity.

The direction of the initial velocity depends on the orientation of the surface in which the orifice is located.The velocity of the jet in the X direction (horizontal) remains constant

Vx = V0 = Cv ?2gh

The velocity in the Y direction is initially zero and there after a function of time and the acceleration of gravity:

Vy = gt

The X coordinate at time t is
X = Vx t = tCv ?2gh


The Y coordinate is

Y = Vavg t= gt2/2

where Vavg =average velocity over period of time t.

The equation for the path of the jet:

X2 = Cv* Cv *4hY

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Kanwarjot Singh

Kanwarjot Singh is the founder of Civil Engineering Portal, a leading civil engineering website which has been awarded as the best online publication by CIDC. He did his BE civil from Thapar University, Patiala and has been working on this website with his team of Civil Engineers.

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