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Things Site Engineers Must Know About Reinforcement and Steel Bars

As Per Indian Guidelines Only.

Clear cover to main reinforcement in
Footings : 50 mm
Raft foundation Top : 50 mm
Raft foundation Bottom/ sides : 75 mm
Strap Beam : 50 mm
Grade Slab : 20 mm
Column : 40 mm (d>12mm) 25 mm (d= 12mm)
Shear Wall : 25 mm
Beams : 25 mm
Slabs : 15 mm or not less than diameter of the bar.
Flat Slab : 20 mm
Staircase : 15 mm
Retaining Wall on Earth : 20/ 25 mm
Water retaining structures : 20 / 30 mm
Sunshade (Chajja) : 25 mm

Hook for stirrups is 9D for one side

No. of stirrups = (clear span/Spanning) + 1

For Cantilever anchorage length for main steel is 69D

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ā€œLā€ for column main rod in footing is minimum of 300mm

Chairs of minimum 12 mm diameter bars should be used.

Minimum diameter of dowel bars should be 12 mm

Lap slices should not be used for bar larger than 36 mm.

In steel reinforcement binding wire required is 8 kg per MT.

Lapping is not allowed for the bars having diameters more than 36 mm.

Minimum number of bars for a square column are 4 and for circular column are 6.

Longitudinal reinforcement should not be less than 0.8% and more than 6% of gross C/S.

Weight of rod per meter length = d2/162 where d is the diameter in mm

All reinforcement shall be free from mill scales, loose rust & coats of paints, oil or any other substances.

Main bars in the slabs shall not be less than 8 mm (HYSD) or 10 mm (Plain bars) and the distributors not less than 8 mm and not more than 1/8 of slab thickness.

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In case of spacing of bars
Provide the diameter of the bar, if the diameter of the bar are equal.
Provide the diameter of the larger bar, if the diameter are unequal.
5mm more than the nominal maximum size of the coarse aggregate.

Things Site Engineers Must Know

Check out the Unit Weights and Conversion which will be required on construction site here

We at engineeringcivil.com are thankful to Er Vikrant for submitting this construction site check list which is of great use to all civil engineers.

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Kanwarjot Singh

Kanwarjot Singh is the founder of Civil Engineering Portal, a leading civil engineering website which has been awarded as the best online publication by CIDC. He did his BE civil from Thapar University, Patiala and has been working on this website with his team of Civil Engineers.

If you have a query, you can ask a question here.

90 comments on "Things Site Engineers Must Know About Reinforcement and Steel Bars"

Manoj B says:

Lapping for
Beam =top bar at mid & Bottom Bars near Column or at column beam junction
Column= Mid of heignt 50 % of reinforcement slpped (Staggred)
Slab = i also dont know.

vipin says:

Sir..can i overlap the coloum steel at the middle of the coloumn….not at the tie beam???

npm says:

can we use 10 mm dia bar in beam

P.Santosh Kumar says:

Is there any thumb rule for allowance of overlaps/splicing in the form of % of the total steel in an RCC element?

indunil says:

hey guys , does any body know a calculation for alternative reinforcements . such as if we are using 12mm and 16mm s insted of using 20mm s , how many bars we has to use and how can we use them . any idea

iyke says:

Just calcuate equivalent area of the reinforcing bar to be used

Anzar says:

Area of steel calculation to be done.

12 dia bar @ 150 mm spacing as per the drawing.but we do not have 12mm at site in that condition
we are going for higher dia (16mm)with area of steel calculation.

step:1

To find sapcing

Formula = d*d/s d1=12mm d2=16mm
s1=150mm s2=?

d1*d1/s1 = d2*d2/s2

12*12/150 =16*16/s2

s2=266.66 mm

Step:2

Area of steel calculation

Formula =3.14*d*d/4

3.14*12*12/4 = 3.14*16*16
113.04mm*mm = 200.96mm*mm

we have to divided by spacing

133.04/s1 =200.96/s2
133.04/150 = 200.96/266.66
0.7536 mm = 0.7536 mm

Hence the spacing the spacing calculation S2 is correct

Step : 3

For sample we are calculating for 4sqm (using 16 dia bar instead of 12mm)

12mm bar @ 150 mm spacing = 4000/150
=26.66 ..say 27 nos of 12mm bar @ 150mm spacing

16mm bar @ 266.66 mm spacing = 4000/266.66
=15.0003 …say 16 nos of 16mm bar @ 266.66 mm spacing

Thank you

saiful says:

What is the percentage of MS rod in pile and pile cap and raft foundation.

RW says:

Presumably these rules/values are for India? You might want to make it clear that these are not some kind of worldwide standard.

Kanwarjot Singh says:

Hi,
Its written this is for India only

pratik says:

lets say there is T12@100c/c to be replaced with T16 due to unavailability of T12.
so area of T12-113.04
area of T16-200.96
no. of T12 in 1 meter = (1000/100)+1 = 11nos.
area of 11T12 bars = (113.04*11)= 1243.44.
therefore no of T16 bars req = 1243.44/200.96 = 7
so the spacing of T16 bars =142.85mm. rounding to 140 c/c.
so T16 bars can be used 7-T16@140c/c

Nivaas says:

what is the gauge of binding wire normally using for Tying of reinforcement?

Altaf Ali Jageerani says:

In general, Lap up to 20mm dia steel is provided 35times the steel diameter,nevertheless above 20mm diameter of steel the lap is provided upto 60 times the steel dia .

Tehzeeb Hussain says:

Dear Sir, Good quality diameter bar How To Testing

MASUM RAZA says:

Can any plz tell me easy way to calculate Quantity of Steel for Raft Foundation

Dharmvir Singh Chaudhary says:

Dear Sir, Please Explain and Calculated Circular Column.

Dharmvir Singh Chaudhary says:

Dear Sir, Please Explain Starting Setting Time Of Concrete.

Supriyo says:

What is the tollerence limit of Clear cover of Column and stirrup length???

Isteyaque Ahmad says:

What is cutting length of steel bar if column size 950×600

T V R says:

Reply:
Calculation of cutting length of stirrup for a column size 950×600:

Clear cover to column to be considered is 40 mm

Formula : Cutting Length = 2(a+b)+2xhook length -(3×90 degree bend + 2×135 degree bend)

Where a = 950-2×40 = 950-80 = 870
b = 600-2×40 = 600-80 = 520
hook length = 9xd where d is dia of bar
= 9×10 if you use 10 mm dia stirrup
deduction for bends = for 90 degree bend deduction is 2xd = 2×10
for 135 degree bend deduction is 3xd = 3×10

Therefore cutting length = 2(870+520)+2x9x10-(3x2x10+2x3x10)
= 2×1390+180-(60+60) = 2780+180-120 = 2840 mm = 2.84 m

Note : The above caluculation will only be the correct where so many persons use to calculate the same in so many different ways without having firm knowledge and hence if any body want to discuss about particularly calculation of cutting length of stirrup only you pl welcome to my mob 6002248094

Thanking you

Nikhil jain says:

Hey guys in above notes there are two pts, Chairs of minimum 12 mm diameter bars should be used.Minimum diameter of dowel bars should be 12 mm what does mean and minimum diameter of which dowel bar.?

viplav patel says:

why top and bottom extra bars provided in the beam at the junction??

S.Hasan says:

Thank u very much.Really useful for civil engineer

DHRUV says:

why the column in L is the 300mm please describe me

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